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Control May Reach End Of Non-Void Function

Control May Reach End Of Non-Void Function. Void *callop() {while(1) {if ('q' == ch) {break;}. My personal guess is that the return statement was meant to one.

Control may reach end of nonvoid function CSDN博客
Control may reach end of nonvoid function CSDN博客 from blog.csdn.net

In c, you must have a value returned. Web if you call the function with a first argument of 0 the loop is never executed and the return statement is, thus, never reached. Web use the return statements at the end of each code path of the function body.

Web If Control Reaches The End Of A Function And No Return Is Encountered, Gcc Assumes A Return With No Return Value.


Hence you are getting an error. My personal guess is that the return statement was meant to one. The method have a path that don't return anything, as commented, when parameter n =.

Web You Must Put A Return On The First Else, In Case Your Method Doesn't Go Through The For Loop, For Example, When X.currentsize = 0.


In c, you must have a value returned. Also, your if condition always. Void *callop() {while(1) {if ('q' == ch) {break;}.

Right Now, If Len Is Less.


Web if for loop break due to i >= n then control comes to the position where i commented and there is no return statement present. Web control reaches the end of a non void function? Web use the return statements at the end of each code path of the function body.

Web If You Call The Function With A First Argument Of 0 The Loop Is Never Executed And The Return Statement Is, Thus, Never Reached.


Web use the return statements at the end of each code path of the function body. However, for this, the function requires a return.

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